The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2 – InterviewSolution

InterviewSolution

1.	The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions isA. `1//3`B. 3C. `1//4`D. 4
Answer» Correct Answer - A (a) `Cr_(2)O_(7)^(2-)+3Sn^(2+)+14H^(+)rarr2Cr^(3+)+3Sn^(4+)+7H_(2)O` 3 moles of `Sn^(2+)` ions are oxidised by `Cr_(2)O_(7)^(2-)` ions =1 mole. 1 mole of `Sn^(2+)` ions are oxidised by `Cr_(2)O_(7)^(2-)` ions = `1//3` mole.

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