The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions isA. `1//3`B. `1//6`C. `2//3`D. `3//4`

The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2

1.	The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions isA. `1//3`B. `1//6`C. `2//3`D. `3//4`
Answer» Correct Answer - A `Cr_(2)O_(7)^(2-)+3Sn^(2+)+14H^(+)rarr 2 Cr^(3+)+3Sn^(4+)+7H_(2)O` 1 mole of `Sn^(2+)` will reduce `1/3` moles of `K_(2)Cr_(2)O_(7)`.

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The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions isA. `1//3`B. `1//6`C. `2//3`D. `3//4`

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