The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions isA. `1//3`B. `3`C. `1//6`D. `6`

The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2

1.	The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions isA. `1//3`B. `3`C. `1//6`D. `6`
Answer» Correct Answer - A `(6e^(-)+Cr_(2)O_(7)^(2-)rarr2Cr^(3+))` `Sn^(2+)rarrSn^(4+)+2e^(-)` Equivalent of `Cr_(2)O_(7)^(2-)= "Equivalent of" Sn^(2+)` `(n=6)` , `(n=2)` `implies1 Eq= 1Eq` `(1)/(6) mol =(1)/(2) mol` `(1)/(3) "mol of" Cr_(2)O_(7)^(2-)= 1 "mol of" Sn^(2+)`.

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The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions isA. `1//3`B. `3`C. `1//6`D. `6`

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