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The number of moles of KMnO_(4) needed to react with one mole of SO_(3)^(2-) in acidic solution is |
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Answer» `4//5` `MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O` OXDIATION half reaction `SO_(3)^(2-=)+H_(2)OrarrSO_(4)^(2-)+2H^(+)+2e^(-)` sinc 1 mole of `SO_(3)^(2-)` gives `2e^(-)` butreduction of 1 mole of `KmnO_(4)` k requires `5 e^(-)` therefore no of MLES of `KMnO_(4)` krequired to react with 1 mole of `SO_(3)^(2-)=2//5` |
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