1.

The number of moles of KMnO_(4) needed to react with one mole of SO_(3)^(2-) in acidic solution is

Answer»

`4//5`
`2//5`
1
`3//5`

Solution :REDUCTION half reactoin
`MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O`
OXDIATION half reaction
`SO_(3)^(2-=)+H_(2)OrarrSO_(4)^(2-)+2H^(+)+2e^(-)` sinc 1 mole of `SO_(3)^(2-)` gives `2e^(-)` butreduction of 1 mole of `KmnO_(4)` k requires `5 e^(-)` therefore no of MLES of `KMnO_(4)` krequired to react with 1 mole of `SO_(3)^(2-)=2//5`


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