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The number of moles of `KMnO_(4)` reduced by `1 "mol of" KI` in alkaline medium isA. One fifthB. FiveC. OneD. Two |
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Answer» Correct Answer - D In alkaline medium `2KMnO_(4)+KI+H_(2)O rarr 2MnO_(2)+2 KOH+KIO_(3)`. |
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