1.

The number of moles of KMnO_(4) reduced by one mole of Kl in alkaline medium is :

Answer»

one
two
five
one-fifth.

Solution :`overset(+7)KMnO_(4) overset(OH^(-))to overset(+6)K_(2)MnO_(4)`
Change in oxidation NUMBER of Mn in basic medium is 1.
`therefore` Moles of Kl is EQUAL to moles of `KMnO_(4)`.


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