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The number of moles of `KMnO_(4)` required to oxidise `1 mol` of `Fe(C_(2)O_(4))` in acidic medium isA. `0.6`B. `1.67`C. `0.2`D. `0.4` |
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Answer» Correct Answer - A `underset((n=5))("Equivalent of "MnO_(4)^(ө)) = underset((n=3))("Equivalent of "Fe(C_(2)O_(4)))` `(1)/(5) mol =(1)/(3) mol` `(3)/(5)"mol of" MnO_(4)^(ө) = 1 "mol of" Fe(C_(2)O_(4))` `0.6 "mol of" MnO_(4)^(ө) = 1 mol Fe (C_(2)O_(4))` |
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