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The number of moles of KMnO_4 that are needed to react completely with one mole of ferrous oxalate in acidic solution is |
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Answer» `1/5` `Fe^(2+) to Fe^(3+) + e^(-)` `C_(2)O_(4)^(2-) to 2CO_(2) + 2e^(-)` `MnO_(4)^(-) + 8H^(+) + 5E^(-) to Mn^(2+) + 4H_(2)O` The OVERALL reaction is: `5Fe^(2+) + 5C_(2)O_(4)^(2-) + 3MnO_(4)^(-) + 24H^(+) to 3Mn^(2+) + 5Fe^(3+) + 10 CO_(2) + 12H_(2)O` Obviously, 5 moles of ferrous OXALATE react with 3 moles of `KMnO_4`. Hence, ONE mole of ferrous oxalate will react with `3/5` moles of `KMnO_(4)`. |
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