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The number of moles of KMnO_4 that will be needed to react completely with one mole of ferrous oxalate in acidic solution is |
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Answer» Solution :`MnO_(4)^(-)+SO_(3)^(-2) RARR Mn^(+2)+SO_(4)^(2-)` change in oxidation of Mn = 5 change in oxidation of S= 2 `2MnO_(4)^(-)+5SO_(3)rarr2Mn^(+2)+5SO_(4)^(2-)` `:.`1 mol of `SO_(3)^(-2) `require `2/5` MOLES `KMnO_4` |
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