1.

The number of moles of lead nitrate needed to coagulate 2 mol of colloidal [AgI]I^(-) is

Answer»

2
1
`1//2`
`2//3`

Solution :`2[AGI]I^(-)+Pb^(2+) rarr PbI_(2)+2AgI`
THUS 2 moles of `[AgI]I^(-)` are coagulated by 1 mole of `Pb^(+)` i.e., 1 mole of Pb `(NO_(3))_(2)`


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