1.

The number of moles of oxygen in 1L of air which contains 21% oxygen by volume under standard conditions is :

Answer»

0.186 MOL
0.21 mol
2.10 mol
0.0093 mol

Solution :22.4 L of `O_(2)=1` mol
`0.21 L` of `O_(2) = (0.21)/(22.4)= 0.0093` mol


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