The number of neutrons in `1*8` g of water will approximately beA. `4*216xx10^(23)`B. `8*432x10^(23)`C. `4*816xx10^(23)`D. `4*216xx10^(24)`

The number of neutrons in `1*8` g of water will approximately beA. `4*

1.	The number of neutrons in `18` g of water will approximately beA. `4216xx10^(23)`B. `8432x10^(23)`C. `4816xx10^(23)`D. `4*216xx10^(24)`
Answer» Correct Answer - C `H_(2)O = 2_(1)^(1)H+._(8)^(16)O` `:.` neutrons, `._(0)^(1)n = 0+8` `.^(2)H_(2)O = (18)/(18) = 01` Hence `._(0)^(1)n = 8xx01xx602xx10^(23)` `=4*816xx10^(23)`

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The number of neutrons in `1*8` g of water will approximately beA. `4*216xx10^(23)`B. `8*432x10^(23)`C. `4*816xx10^(23)`D. `4*216xx10^(24)`

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The number of neutrons in `18` g of water will approximately beA. `4216xx10^(23)`B. `8432x10^(23)`C. `4816xx10^(23)`D. `4*216xx10^(24)`