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The number of optical isomers for the compound, `CH_(3)-CH(Br)-CH(Br)C_(2)H_(5)` isA. 1B. 2C. 4D. 3 |
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Answer» Correct Answer - C The compound `CH_(3)-CH(Br)CH(Br)C_(2)H_(5)` cannot be divided into two identical halves. It has 2 chiral centres. The formula for number of optically active form is `2^(n)`. Where n is the number of chiral centres. Hence `2^(2) = 4` Hence the number of isomers are 4 so choice (a), (b) and (d) are incorrect while (c) is correct. |
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