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The number of optical isomers of `CH_(3)CH(OH)CH(OH)CHO` isA. ZeroB. 2C. 3D. 4 |
Answer» Correct Answer - D `CH_(3)-underset(OH)underset(|)overset(H)overset(|)(C^(**))-overset(H)overset(|)underset(OH)underset(|)(C^(**))-CHO` It has 2 optically active carbon atoms and it has no plane of symmetry. So, number of optical isomers `= 2^(2) = 4`. |
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