The number of optically active isomers possible for the compound CH_(3)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-CH_(2)OH

The number of optically active isomers possible for the compound CH_(

1.	The number of optically active isomers possible for the compound CH_(3)-underset(OH)underset(\|)(CH)-underset(OH)underset(\|)(CH)-underset(OH)underset(\|)(CH)-CH_(2)OH
Answer» 3 4 8 6 Solution :The MOLECULE is not symmetrical and there are THREE chiral carbon atoms i.e., `n = 3` `:.` The number of ISOMERS `= 2^(n) = 2^(3) = 8`.