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The number of ordered real pairs (x,y) with 0<x,y<1 satisfying the simultaneous equation 1+√1−x2x=1+2y1−y+√1−y2 and 25(1−x2)=17−10√1−y2 is |
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Answer» The number of ordered real pairs (x,y) with 0<x,y<1 satisfying the simultaneous equation 1+√1−x2x=1+2y1−y+√1−y2 and 25(1−x2)=17−10√1−y2 is |
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