1.

The number of oxygen atoms in 4.4g of CO_(2) is

Answer»

`1.2xx10^(23)`
`6xx10^(22)`
`6xx10^(23)`
`12XX10^(23)`

Solution :44 g of `CO_(2)" CONTAIN" = 6.023xx10^(23)`molecules of `CO_(2)`
4.4g of `CO_(2)` will contain = `6.023xx10^(23)/(44)xx4.44`
`=6.023xx10^(22)` molecules of `CO_(2)~
`1molecule of `CO_(2)` contains two oxygen ATOMS
`6.023xx91^(22)` molecules of `CO_(2)` will contain
`2xx6.023xx10^(22)=1.210^(23)`oxygen atoms


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