1.

The number of oxygen atoms present in 14*6 g of magnesium bicarbonate is

Answer»

`6N_(0)`
`0*6N_(0)`
`N_(0)`
`N_(0)//2`

Solution :Magnesium bicarbonate is `MG(HC)_(3))_(2)` 146 g of `Mg((HCO_(3))_(2)` contains O ATOMS = `6N_(0)`
`:. 14*6 g` of `Mg(HCO_(3))_(2)` contains O ATOM
`=0*6 N_(0)`


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