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The number of photons frequency 1014 Hz in radiation of 6.62 Joule will be A) 1010B) 1015 C) 1020 D) 1025 |
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Answer» The correct option is C) 1020 Since E = hv Where E = Energy h = Planck’s constant and v = frequency. Given; E = 6.62 J v = 1014 Hz Let the no. of photons be x. =) E = (x) x (hv) =) 6.62 = (x) x (6.62 x 10-34 Js) x 1014 =) 6.62/6.62 = (x) x (10-20) =) 1 = (x) x (1)/ 1020 =) 1020 = x. |
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