1.

The number of photons frequency 1014 Hz in radiation of 6.62 Joule will be A) 1010B) 1015 C) 1020 D) 1025

Answer»

The correct option is C) 1020

Since E = hv 

Where E = Energy 

h = Planck’s constant and v = frequency. 

Given; 

E = 6.62 J 

v = 1014 Hz 

Let the no. of photons be x. 

=) E = (x) x (hv) 

=) 6.62 = (x) x (6.62 x 10-34 Js) x 1014 

=) 6.62/6.62 = (x) x (10-20

=) 1 = (x) x (1)/ 1020 

=) 1020 = x.



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