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The number of positive six-digit integers which are divisible by `9` and four of its digits are `1`, `0`, `0`, `5` isA. `60`B. `120`C. `180`D. `210` |
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Answer» Correct Answer - C `(c )` The sum of digits must be divisible by `9` The pair of missing numbers must be `(1,2)` or `(0,3)` Case I : `(1,2)` `implies` when `1` is first digit the remaining digits `(1,2,0,0,5)` can be arranged in `60` days, when `5` or `2` is first digit then in `30` ways each Case II : `(0,3)` will have `3xx20=60` ways So total number of ways `=60+2xx30+3xx20=180` |
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