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The number of possible enantiomeric pairs that can be produced during mono-chlorination of 2-methylbutane isA. 3B. 4C. 1D. 2 |
Answer» Correct Answer - D `{:(overset(1)(C)H_(3)-overset(2)(C)H-overset(3)(C)H_(2)-overset(4)(C)H_(3)),(" |"),(" "CH_(3)):}` Its monochloro derivatives are as follows : (i) `{:(ClCH_(2)-overset(*)(C)H-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}` or `{:(CH_(3)-overset(*)(C)H-CH_(2)-CH_(3)),(" |"),(" "CH_(2)Cl):}` It will exist as enantiomeric pair (d and l-forms) (ii) `{:(" "Cl),(" |"),(CH_(3)-C-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}` no asymmetric C-atom (iii) `{:(" "Cl),(" |"),(CH_(3)-CH-CH-CH_(3)),(" |"),(" "CH_(3)):}` It will exist as enantiomeric pair (d-and l-forms) (iv) `{:(CH_(3)-CH-CH_(2)-CH_(2)-Cl),(" |"),(" "CH_(3)):}` No asymmetric carbon atom Hence, only two enantiometric pairs will be obtained by the monochlorination of 2-methylbutane. |
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