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The number of possible outcomes in a throw of n ordinary dice in which at least one of the dice shows an odd number isA. `6^(n)-1`B. `3^(n)-1`C. `6^(n)-3^(n)`D. `6^(n)-5^(n)` |
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Answer» Correct Answer - C The total number of ways is `6xx6xx…` to n times `=6^(n)` the total number of ways to show only even number is `3xx3`… to n times `=3^(n)` therefore the required number of ways is `6^(n)-3^(n)`. |
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