1.

The number of quanta of radiations of frequency 4.75xx10^(13)s^(-1) required to melt100g of ice is (energy required to melt 1 g of ice is 350J)

Answer»

`1.113xx10^(23)`
`111.3xx10^(23)`
`11.13xx10^(23)`
`1.113xx10^(22)`

SOLUTION :Energy of a QUANTUM
`=6.63xx10^(-34)Jsxx4.75xx10^(13)s^(-1)`
`=3.15xx10^(-20)J`
Energy required `=100xx350=3.50xx10^(4)`
NO.of quanta `=(3.50xx10^(4))/(3.15xx10^(-20))`
`=11.13xx10^(23)`


Discussion

No Comment Found

Related InterviewSolutions