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The number of real negative terms in the binomial expansion of `(1+i x)^(4n-2),n in N ,x >0`isA. nB. n+1C. n-1D. 2n |
Answer» Correct Answer - A `T_(r+1) = .^(4n-2)C_(r)("ix")^(r )` `T_(r+1)` is negative, if `i^(r)` is negative and real. `i^(r ) = - 1` `rArr r = 2, 6, 10,"……"` which form an `A.P.` `0 le r le 4n - 2` `4n - 2 = 2 + (r-1)4` `rArr r = n` The required number of terms is n. |
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