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InterviewSolution
| 1. |
The number of real roots of the equation (x − 1)2 + (x − 2)2 + (x − 3)2 = 0 is : (a) 3 (b) 0 (c) 1 (d) 2 |
| Answer» <p style="text-align:justify"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (b) 0</strong></span></span></p><p style="text-align:justify"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong> Explanation:</strong></span></span></p><p style="text-align:justify"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">We have (x − 1)<sup>2</sup> + (x − 2)<sup>2</sup> + (x − 3)<sup>2</sup> = 0 (x − 1)<sup>2</sup> , (x − 2)<sup> 2</sup> , (x − 3)<sup>2 </sup> cannot be zero simultaneously for any real value of x. </span></span></p><p style="text-align:justify"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">∴ their sum will have be zero. </span></span></p><p style="text-align:justify"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Hence, number of roots = 0.</span></span></p> | |