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The number of real roots of the equation (x − 1)2 + (x − 2)2 + (x − 3)2 = 0 is : (a) 3 (b) 0 (c) 1 (d) 2 |
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Answer» Correct option (b) 0 Explanation: We have (x − 1)2 + (x − 2)2 + (x − 3)2 = 0 (x − 1)2 , (x − 2) 2 , (x − 3)2 cannot be zero simultaneously for any real value of x. ∴ their sum will have be zero. Hence, number of roots = 0. |
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