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the number of real solutions of equation is: sqrt(1 + cos2x) = sqr(2).sin^-1(sinx) x belongs to [-pi, pi] options: 0, 1, 2, infinite

Answer» the number of real solutions of equation is:
sqrt(1 + cos2x) = sqr(2).sin^-1(sinx)
x belongs to [-pi, pi]
options: 0, 1, 2, infinite


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