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The number of real solutions of the equation 2|x|2 – 5|x| + 2 = 0 is :(a) 0 (b) 4 (c) 2 (d) None of these |
Answer» (b) 4 2| \(x\) |2 – 5| \(x\) | + 2 = 0 ⇒ (2| \(x\) | – 1) (| \(x\) | – 2) = 0 ⇒ | \(x\) | = \(\frac{1}{2}\), 2 ⇒ x = ± \(\frac{1}{2}\), ± 2 So, there are 4 solutions. |
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