1.

The number of real solutions of the equation 2|x|2 – 5|x| + 2 = 0 is :(a) 0 (b) 4 (c) 2 (d) None of these

Answer»

(b) 4

2| \(x\) |2 – 5| \(x\) | + 2 = 0 

⇒ (2| \(x\) | – 1) (| \(x\) | – 2) = 0 

⇒ | \(x\) | = \(\frac{1}{2}\), 2 ⇒ x = ± \(\frac{1}{2}\), ± 2 

So, there are 4 solutions.



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