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The number of silicon atoms per `m^(3) is 5xx10^(28)`. This is doped simultaneously with `5xx10^(22)` atoms per `m^(3)` of Arsenic and `5xx10^(20) per m^(3)` atoms of indium. Calculate the number of electrons and holes. Given that `n_(i)=1.5xx10^(16)m^(-3)`. Is the material n-type or p-type? |
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Answer» `n_(e)=5xx10^(22)-5xx10^(20)=(5-0.05)xx10^(22)=4.95xx10^(22)m^(-3)` `n_(h)=n_(i)^(2)/n_(e)=((1.5xx10^(16))^(2))/(4.95xx10^(22))=4.54xx10^(9)m^(-3)` As `n_(e) gt n_(h)`, so the material is n-type semiconductor. |
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