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The number of solution of the equation `log(-2x)= 2 log(x+1)` areA. `3`B. `2`C. `1`D. `0` |
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Answer» Correct Answer - C The number of solutions ……………….. Given, `log(-2x)=2log(x+1)` `implies -2x = (x+1)^(2)` `implies x^(2)+4x+1=0` `implies x = (-4+-sqrt(16-4))/(2) implies x = (-4+-sqrt(12))/(2)` `implies x = (-2+sqrt(3)), (-2, -sqrt(3))` `x+1gt0 and -2 x gt 0` Hence `x = - 2 + sqrt(3)` |
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