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The number of solution(s) of 1+logx(4−x10)=(log10log10n−1)logx10 for a given value of n∈(1,104)−{103} is |
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Answer» The number of solution(s) of 1+logx(4−x10)=(log10log10n−1)logx10 for a given value of n∈(1,104)−{103} is |
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