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The number of solution(s) of the equation 2cos2x−2√2cosx+tan2x−2tanx+2=0 where x∈[−4π,4π] is |
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Answer» The number of solution(s) of the equation 2cos2x−2√2cosx+tan2x−2tanx+2=0 where x∈[−4π,4π] is |
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