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The number of solutions of x2 + |x - 1| = 1 is A. 0 B. 1 C. 2 D. 3 |
Answer» when x > 0 x2 + x-1 = 1 x2 + x - 2 = 0 (x-1) (x+2) = 0 x = 1, -2 when x < 0 x2 - x+1 = 1 x2 – x = 0 x(x-1) = 0 x = 0, 1 hence the given equation has 3 solutions and they are x = 0, 1, -1. |
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