1.

The number of solutions of x2 + |x - 1| = 1 is A. 0 B. 1 C. 2 D. 3

Answer»

when x > 0 

x2 + x-1 = 1 

x2 + x - 2 = 0 

(x-1) (x+2) = 0 

x = 1, -2 

when x < 0 

x2 - x+1 = 1 

x2 – x = 0 

x(x-1) = 0 

x = 0, 1 

hence the given equation has 3 solutions and they are x = 0, 1, -1.



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