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The number of terms of the A.P. 3, 7, 11, 15, ... to be taken so that the sum is 406 is(a) 5(b) 10(c) 12(d) 14(e) 20 |
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Answer» The number of terms of the A.P. 3, 7, 11, 15, ... to be taken so that the sum is 406 is (a) 5 (b) 10 (c) 12 (d) 14 (e) 20 |
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