1.

The number of unit cells in 8 gm of an element X (atomic mass 40) which crystallizes in bcc pattern is (N_(A)" is the Avogadro number")………………. .

Answer»

`6.023xx10^(23)`
`6.023xx10^(22)`
`60.23xx10^(23)`
`((6.023xx10^(23))/(8xx40))`

Solution :Hint : In BCC unit cell, 2 atoms `-=` 1 unit cell
Number of atoms in 8g of element is, Number of moles `=(8g)/("40g, MOL"^(-1))=0.2 mol`
`"1 MOLE contains "6.023xx10^(23)" atoms"`
`"0.2 mole contains"0.2xx6.023xx10^(23)" atoms"`
`(("1 unit cell")/("2 atoms"))xx0.2xx6.023xx10^(23)""6.023xx10^(22)" unit cells"`


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