1.

The number of unit cells in the `Ca` atom lies on the surface of a cubic crystal that is `1.0 cm` in length isA. `9.17 xx 10^(23)`B. `9.17 xx 10^(22)`C. `2 xx 9.17 xx 10^(23)`D. `2 xx 9.17 xx 10^(22)`

Answer» Correct Answer - B
Volume of crystal `= (1.0 cm)^(3) = (10^(-2)m)^(3) = 10^(-6) m^(3)`
Number of unit cells `= (10^(-6)m^(3))/(10.9 xx 10^(-3) m^(3)) = 9.17 xx 10^(22)`


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