1.

The number of unpaired electrons in [NiCl_(4)]^(2-), Ni(CO)_(4) and [Cu(NH_(3))_(4)]^(2+) respectively are

Answer»

2,2,1
2,0,1
0,2,1
2,2,0

Solution :In `[NiCl_(4)]^(2-)`, Ni is in +2 oxidation STATE.

Unpaired electrons =2
In `Ni(CO)_(4),Ni` is in zero oxidation state.
`Ni:(AR]3d^(8)4s^(2)`

Co is STRONG field ligand and causes pairing of electron of 4s to 3d.
`Ni(CO)_(4)`

Unpaired electron =0
In `[Cu(NH_(3))_(4)]^(2+)`, Cu is in +2 oxidation state.
`Cu^(2+): [Ar]3d^(9)4s^(0)`
`[Cu(NH_(3))_(4)]^(2+)`

Unpaired ELECRTRON =1


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