Saved Bookmarks
| 1. |
The number of unpaired electrons in the square planar [Pt(CN)_(4)]^(2-) ion is |
|
Answer» Solution :In the given compled `[Pt(CN)_(4)]^(2-)` The electron configuration of Pt `Pt to [Xe]4f^(14)5D^(9)6s^(1)` `Pt^(2+)to[Xe]4f^(14)5d^(8)`  In has zero UNPAIRED electron as `CN^(-)` is a strong field ligand. |
|