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The number of values of the pair (a, b) for which `a(x+1)^2 + b(-x^2 – 3x - 2) + x + 1 = 0` isan identity in x, is |
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Answer» Correct Answer - B We have, `a(x + 1)^(2) + b(-x^(2) - 3x - 2) + x + 1 = 0` `rArr" "x^(2) (a-b) + x(2a - 3b + 1) + a - 2b + 1 = 0` For this to be an identity in x, we must have `a-b=0, 2a-3b + 1 = 0 and a - 2b + 1 = 0` `rArr" "a = b = 1` Hence, there is only one pair (1, 1). |
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