The number of water molecules in a drop of water weighing 0.018 g is

1.	The number of water molecules in a drop of water weighing 0.018 g is
Answer» `6.022xx10^(26)` `6.022xx10^(23)` `6.022xx10^(20)` `9.9xx10^(22)` SOLUTION :WEIGHT of the water drop=0.018g No. of moles of water in the drop=Mass of water/molar mass =0.018/18=`10^(-3)` mole No of water molecules present in 1 mole of water =`6.022xx10^(23)` No. water molecules in one drop of water (`10^(-3)` mole)=`6.022xx10^(23)xx10^(-3)` `=6.022xx10^(20)`

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