1.

The number of water molecules present in a drop of water (volume = 0.0018mL) at room temperature is

Answer»

`1.084 xx 10^(18)
`6.023 xx 10^(23)`
`3.01 xx 10^(23)`
`6.023 xx 10^(23)`

SOLUTION :B) Number of moles = (Weight)/(Molecular weight)
`=(0.0018)/(18) = 1 xx 10^(-4)`
[`therfore` 0.0018 mL = 0.0018g]
Number of water MOLECULES `=1 xx 10^(-4) xx 6.023 x 10^(23)`
`=6.023 xx 10i^(19)`


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