1.

The number of water molecules present in a drop of water weighing 0.18g is :

Answer»

`6.022 xx 10^26`
`6.022 xx 10^23`
`6.022 xx 10^19`
`6.022 xx 10^21`

Solution :MOLES of water in a DROP
` = (0.018)/(18) = 1 xx 10^(-3) ` moles
1MOL of water ` = 6.022 xx 10^23` molecules
` 1 xx 10^(-3) ` mole ofwater
` = 6.022 xx 10^23 xx 1 xx 10^(-3)`
` = 6.022 xx 10^20` molecules


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