| 1. |
The number of ways in which 4 boys and 4 girls can be arranged in a row so that no two girls and no two boys are together is1. (4!)22. 2(4!)23. 8!4. None of these |
|
Answer» Correct Answer - Option 2 : 2(4!)2 Calculation: Given: 4 boys and 4 girls can be arranged in a row so that no two girls and no two boys are together. It means they can sit alternately Case-I: 1st person in the row is a boy. B1G1B2G2B3G3B4G4 The no. of ways in which the boys can be rearranged among themselves is 4!. Case-II:1st person in the row is a girl. G1B1G2B2G3B3G4B4 The no. of ways in which the girls can be rearranged among themselves is 4!. Hence, Total Number of ways = (4!)2 + (4!)2 = 2(4!)2 |
|