1.

The number of ways in which 4 boys and 4 girls can be arranged in a row so that no two girls and no two boys are together is1. (4!)22. 2(4!)23. 8!4. None of these

Answer» Correct Answer - Option 2 : 2(4!)2

Calculation:

Given: 4 boys and 4 girls can be arranged in a row so that no two girls and no two boys are together.

It means they can sit alternately

Case-I: 1st person in the row is a boy.

B1G1B2G2B3G3B4G4

The no. of ways in which the boys can be rearranged among themselves is 4!. 
Similarly, The no. of ways in which the girls can be rearranged among themselves is 4!.
So, the total number of ways = 4! × 4! = (4!)2

Case-II:1st person in the row is a  girl.

G1B1G2B2G3B3G4B4

The no. of ways in which the girls can be rearranged among themselves is 4!. 
Similarly, The no. of ways in which the boys can be rearranged among themselves is 4!.
So, the total number of ways = 4! × 4! = (4!)2

Hence, Total Number of ways =  (4!)+ (4!)= 2(4!)2



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