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The number of ways in which ten candidates A, AAo can be ranked such that A, ls always above Ao ls(D)101)10(A) 5!(B) 2(5)(C) 10 |
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Answer» Total number of ways to arrange a1 .. a10 = 10!In 10! / 2 combinationsa1 will be above a2 and in the other half a2 will be above a1. Ans : 10! / 2 |
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