1.

The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. Find the remainder when this 100 digit number is divided by 9. 1). 12). 43). 34). 2

Answer»

SINCE the number is of 100 digits and 3446, 5887 and 2445 are put side by side in the same ORDER;

∴ 3446 must be repeated 9 times, 5887 & 2445 must be repeated 8 times;

SUM of digits of 100 digits number = [3 + 4 + 4 + 6] × 9 + [5 + 8 + 8 + 7 + 2 + 4 + 4 + 5] × 8

⇒ 153 + 344

⇒ 497

Reminder when 497 is divided by 9 = 2

Hence, the remainder when the 100 digit number is divided by 9 would be 2.


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