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The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. Find the remainder when this 100 digit number is divided by 9. 1). 12). 43). 34). 2 |
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Answer» SINCE the number is of 100 digits and 3446, 5887 and 2445 are put side by side in the same ORDER; ∴ 3446 must be repeated 9 times, 5887 & 2445 must be repeated 8 times; ∴ SUM of digits of 100 digits number = [3 + 4 + 4 + 6] × 9 + [5 + 8 + 8 + 7 + 2 + 4 + 4 + 5] × 8 ⇒ 153 + 344 ⇒ 497 Reminder when 497 is divided by 9 = 2 Hence, the remainder when the 100 digit number is divided by 9 would be 2. |
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