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you are study in 11th standard

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6.02×10^3 moles

no

ans. h 2.4 × 10 ^ 25

or 6.02 ×10^56

tu kaha jara

ok soooory....

Since density of water is 1 gm/cc, 72 ml corresponds to mass m =72 g of water.

so, no. of moles corresponding to 72 g = m/A = 72/18=3, where A is molecular wt (water =72 g)

Now, 1 mole of water contains 6.022*10^23 molecules of H2O and

one molecule of H2O contains 10 electrons (i.e. There are 8 electrons in oxygen and 1 from each hydrogen so a water molecule has 10 electrons).

Hence, total no. of electrons present in 72 ml of water =3*10 * 6.022*10^23

= 6.022*10^24*3

= 18.066*10^24

pooja u r also wrong

ok

I'm pooja

im not saying to u

are u angry

no

q

I think so

okkk

where do u live

tujhe ky karna h me kaha bhi rhu

Please do not use this forum for conversartions irrelated to studies

yaar bye sorry

okktell to jatin aldo

okkk

tell Richa also

just go to hell

Please

u first stsrted the conversation

I think you are living in a hell

uuhh! I asked related to your question

pooja plz help

give ans. for this question

POOJA plz help

POOJA.. ..:-)

where r u pooja

in the hell

plzz dont use this words to her

Here we will use the the concept of density of water = 1g/ccD=M/V1 g/ml = M/72 mlM= 72 gmoles of water = mass/molar mass = 72/72 = 11 mole of water contains = NAmoleculestotal electrons in water = 2(H) + 8(O) = 101 molecule of water contains = 10 electrons1 mole water contains = 10 * NAelectronsNA= Avogadro’s number

= 6.022 × 10^24

2.4×10^25 is the answer

Hope so it is right :-)

thnx

Welcm richa