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The numerical value of solubility product of magnesium hydroxide at 25^@ C is 3.2 xx 10^(-11). What is its solubility ?

Answer»

Solution :The solubility equilibrium of magnesium hydroxide, `Mg(OH)_2 hArrMg^(2+) + 2OH^(-)`
If the solubility is x for `AB_2` type SUBSTANCE, solubility product is `4x^3`.
`4x^3 = 3.2 xx 10^(-11) , x = 8 xx10^(-12)` and hence, `x = 2 xx 10^(-4)`
Solubility of `Mg(OH)_2= 2 x x 10^(-4)MOL L^(-1)`


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