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The O.N of N in `(NH_(4)_(2) SO_(4))` is :A. `+3`B. `+2`C. `+5`D. `-3` |
Answer» Correct Answer - D In `NH_(4)^(+)` ion : `overset(x+1)[NH_(4)]^(+)` x+4(1)=+1,x=-3 O.N of N=-3 |
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