1.

The O.N of P in Ba(H_(2)PO_(2))_(2) is:

Answer»

`+3`
`+2`
`+1`
`-1`

Solution :`Ba(H_(2)OVERSET(x)PO_(2))_(2)`
+2 + 4 (+1) + 2 x + 4 (-2)=0
2x-2=0 or x=+1


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