1.

The observed value of dipole moment of H_(2)O molecule is found to be 1 .84 D. Calculate the H-O-H bond angle in H_(2)O molecule , given that the bond moment of O-H bond is 1.5 D.

Answer»

Solution :As dipole monent of `H_(2)O`is the resultant of the two vactors(O-H BONDS), therefore ,if `ALPHA ` is the angle
between the two vactors , then
`mu=sqrt(mu_(1)^(2) + mu_(2)^(2) + 2mu_(1) mu_(2) cos alpha )`
`mu_(H_(2)O=sqrt(mu_(OH)^(2) + mu_(OH)^(2) + 2mu_(OH)^(2) cos alpha ))`
`1.84 = sqrt((1.5)^(2) + (1.5)^(2)+2 (1.5)^(2) cos alpha)`
or`3.3856 = 2.25 + 2.25 + 4.50 cos alpha or cos alpha= -0.2476`
or `alpha = 104^(@) 20'[cos (180 - THETA )= - cos theta, i.e.,cos (180 - alpha ) = 0.2476 or 180 - alpha = 75^(@)40']`


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