The opposite faces of a cubical block of iron of cross-section 4 xx 10^(-4) "m"^(2) are kept in contact with steam and melting ice. Calculating the amount of ice melted at the end of 5 minutes. Given K=0.2 cal cm ""^(-1) "s"^(-1)°"C"^(-1).

The opposite faces of a cubical block of iron of cross-section 4 xx 10

1.	The opposite faces of a cubical block of iron of cross-section 4 xx 10^(-4) "m"^(2) are kept in contact with steam and melting ice. Calculating the amount of ice melted at the end of 5 minutes. Given K=0.2 cal cm ""^(-1) "s"^(-1)°"C"^(-1).
Answer» SOLUTION :`m = KA ( theta_1 - theta_2) t // ANGLE x = ( 84) xx 4 xx 10^(-4)xx 100 xx 5 xx 60//336 xx 10^(3)xx 2 xx 10^(-2)= 0.15 "KG"`